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3x^2-80x+170=0
a = 3; b = -80; c = +170;
Δ = b2-4ac
Δ = -802-4·3·170
Δ = 4360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4360}=\sqrt{4*1090}=\sqrt{4}*\sqrt{1090}=2\sqrt{1090}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-2\sqrt{1090}}{2*3}=\frac{80-2\sqrt{1090}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+2\sqrt{1090}}{2*3}=\frac{80+2\sqrt{1090}}{6} $
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